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Jan 10 Sat 2015 03:44
Android: One line code to have multi-image in one viewpager

Your problem is similar to one CommonWare's blog. Multiple-View ViewPager Options There are three approach. One of those is override getPageWidth() in your PagerAdapter:

@Overridepublicfloat getPageWidth(int position){return(0.5f);}

The others is more complicated but there're attach source and long explanation so i don't copy here.

resource url : http://stackoverflow.com/questions/13194666/how-to-set-viewpager-size

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May 18 Sat 2013 02:00
Java Code: Upload files to php server

public static void Update() throws Exception {

    HttpClient httpclient = new DefaultHttpClient();

    httpclient.getParams().setParameter(

    CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);

    

    HttpPost httppost = new HttpPost("http://mpss.csce.uark.edu/~tsumar/test/upload_file.php");

    File file = new File("image.jpg");

    

    MultipartEntity mpEntity = new MultipartEntity();

    ContentBody cbFile = new FileBody(file, "image/jpeg");

    mpEntity.addPart("file", cbFile);

    

    httppost.setEntity(mpEntity);

    System.out.println("executing request " + httppost.getRequestLine());

    HttpResponse response = httpclient.execute(httppost);

    HttpEntity resEntity = response.getEntity();

    

    System.out.println(response.getStatusLine());

    if (resEntity != null) {

        System.out.println(EntityUtils.toString(resEntity));

    }

    if (resEntity != null) {

        resEntity.consumeContent();

    }

    

    httpclient.getConnectionManager().shutdown();

}

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May 13 Mon 2013 02:21
how to download image from any web page in java

Image image = null;
try 
    URL url = new URL("http://www.yahoo.com/image_to_read.jpg");
    image = ImageIO.read(url);
} catch (IOException e) {
}


See javax.imageio package for more info. That’s using the AWT image. Otherwise you could do:


 URL url = new URL("http://www.yahoo.com/image_to_read.jpg");
InputStream in = new BufferedInputStream(url.openStream());
ByteArrayOutputStream out = new ByteArrayOutputStream();
byte[] buf = new byte[1024];
int n = 0;
while (-1!=(n=in.read(buf)))
{
   out.write(buf, 0, n);
}
out.close();
in.close();
byte[] response = out.toByteArray();


And you may then want to save the image so do:

FileOutputStream fos = new FileOutputStream("C://borrowed_image.jpg");
    fos.write(response);
    fos.close();

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Oct 02 Tue 2012 10:23
Swap Variables in C without using Temporary Variable

Reference Link : http://offclassroom.com/off-classroom/cc/282-swap-variables-in-c-without-using-temporary-variable.html

Hello friends! Being a final year computer engineering student, I have gone through so many C programming logics as a preparation of Interview (unfortunately still haven't got a chance to face it :-)
Recently one of my friends cleared the first two rounds of aptitude & programming and then got a chance to face the interview. He was asked so many logical questions on C & C++ . One of those question was, “How many different methods do you know to swap two variables without using a temporary variable?”

From this question, we can't give a particular answer as there might be so many logical solutions that can be used to swap two variables. I certainly know three:

Method 1: Swap two variables using + & - operators

a = a+b;
b = a-b;
a = a-b;

lets take a=10 & b=5,

a = a+b = 10+5 = 15      so, a=15 & b=5
b = a-b = 15-5 = 10        so, a=15 & b=10
a = a-b = 15-10 = 5       so, a=5 & b=10

Thus a=5 & b=10, values are swapped.
This is the most popular method for swapping two variables but still this method has one drawback. If a and b are big and their addition is bigger than the size of integer than this might end up giving you wrong results.

Method 2 : Using X-OR (^) operator

a = a^b;
b = b^a;
a = a^b;

lets take a same example a=10 & b=5,

a = a^b = 10^5 = 15        so, a=15 & b=5
b = b^a = 5^15 = 10        so, a=15 & b=10
a = a^b =15^10 = 5         so, a=5 & b=10

Drawback of this method is that it will not work for floating-point values.

Method 3 : Using Pointers

We can overcome the drawback of Method 2 if we use pointers.

swap(int *a, int *b)
{
*a = *a^*b;
*b = *b^*a;
*a = *a^*b;
}

We still have some problem with this method if use X-OR (^)
Now suppose, by mistake, your code passes the pointer to the same variable to this function. Since Xor'ing an element with itself sets the variable to zero, this routine will end up setting the variable to zero (ideally it should have swapped the variable with itself).
One solution to this problem is to check if the numbers to be swapped are already equal to each other.

swap(int *a, int *b)
{
if(*a!=*b)
{
*a = *a^*b;
*b = *b^*a;
*a = *a^*b;
}
}

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